HIGH
V?
LOW
POTENTIAL
ENERGY
+12 V
0 V
V₁ = 6.0 V
+
−
12 V
BATTERY
R1 = 50 Ω
RESISTOR 1
R2 = 50 Ω
RESISTOR 2
A
0.120 A
AMMETER
V
6.00 V
VOLTMETER 1
V
6.00 V
VOLTMETER 2
ΔV = 6.0V
V = V₁ + V₂
12 = 6 + 6
I = V ÷ (R1+R2)
I = 0.120 A
R1
50 Ω
R2
50 Ω
V
12 V
Supply V
12.0
VOLTS
V across R1
6.00
VOLTS
V across R2
6.00
VOLTS
Current
0.120
AMPS
R1 + R2
100
OHMS